F(x)=2*x^2-4.5*x^2+x+10.5

Solution for F(x)=2*x^2-4.5*x^2+x+10.5 equation:

(F)=2F^2-4.5F^2+F+10.5

We move all terms to the left:

(F)-(2F^2-4.5F^2+F+10.5)=0

We get rid of parentheses

-2F^2+4.5F^2-F+F-10.5=0

We add all the numbers together, and all the variables

2.5F^2-10.5=0

a = 2.5; b = 0; c = -10.5;
Δ = b2-4ac
Δ = 02-4·2.5·(-10.5)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{105}}{2*2.5}=\frac{0-\sqrt{105}}{5}
=-\frac{\sqrt{}}{5}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{105}}{2*2.5}=\frac{0+\sqrt{105}}{5}
=\frac{\sqrt{}}{5}
$